bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes, let's find firstly the slope of AC.
![\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-1}{1-2}\implies \cfrac{5}{-1}\implies -5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{-5}}\qquad \stackrel{negative~reciprocal}{\cfrac{1}{5}}}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B1%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B1%7D~%2C~%5Cstackrel%7By_2%7D%7B6%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B6-1%7D%7B1-2%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B-1%7D%5Cimplies%20-5%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperpendicular%20lines%20have%20%5Cunderline%7Bnegative%20reciprocal%7D%20slopes%7D%7D%20%7B%5Cstackrel%7Bslope%7D%7B%5Ccfrac%7B-5%7D%7B1%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7Breciprocal%7D%7B%5Ccfrac%7B1%7D%7B-5%7D%7D%5Cqquad%20%5Cstackrel%7Bnegative~reciprocal%7D%7B%5Ccfrac%7B1%7D%7B5%7D%7D%7D)
so, we're really looking for the equation of a line whose slope is 1/5 and that passes through (3,3)
4/12 / 1/12 & 4/12 / 48/12 are how you make them equal, although i'm not sure about the rest
Answer:
0 < x < 3
Step-by-step explanation:
3 < x + 3 < 6
Subtract 3 from all sides
3-3 < x + 3-3 < 6-3
0 < x < 3
For this problem, we can use systems of equations. I will use the variables <em>x </em> (for ice-cream) and <em>y</em> (for soda). We get the system:
2.25x+0.75y=30.00
x+y=18
Putting the second equation in terms of y, we get that y=-x+18. We can substitute this into our first equation.
2.25x+0.75y=30.00
becomes
2.25x+0.75(-x+18)=30
Solving for x, we get that x=11. This satisfies answer B.
However, if you want to check to see if this is correct, you could find y by plugging in your value of x into the first equation, then check to see if your found values satisfy BOTH equations.
2.25(11)+0.75y=30
24.75+0.75y=30
0.75y=5.25
y=7
Then we plug this into both equations to see if they are true.
2.25(11)+0.75(7)=30
24.75+5.25=30
30=30 (This is true)
x+y=18
11+7=18
18=18 (This is true).
Both equations are true, so the value for x and y are correct. We see that only answer B is supported through analyzing your work.
:)
