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3 years ago

14

Sylvie is going on vacation. She has already driven 58 miles in one hour. If she then travels for 6 hours at an average speed of

60 miles per hour, what is the total distance that Sylvie will have driven?
348 miles

418 miles

358 miles

360 miles

1 answer:

Vlada [557]3 years ago

8 0

The answer would be 360 miles

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Lian is paid for SR 75 per hour. Using p for her pay and h for the hours of work, which function rule represents

Andru [333]

Answer:

The function p = 75h represents this situation.

Step-by-step explanation:

We know the equation of linear equation in the slope-intercept form is

$y = mx+b$

where

m = rate of change = slope

b = y-intercept

Let 'h' be the number of hours

Let 'p' be the pay

Given that Lian is paid SR 75 per hour.

so the rate of change of slope = m = 75

As there is no initial condition, so b = 0

as

y = mx+b

Now, mapping the information data into the slope-intercept form

p = y

m = 75

h = x

b = 0

Thus, the equation becomes

p = 75h

Therefore, the function p = 75h represents this situation.

VERIFICATION:

Given the equation

p = 75h

for h = 1

p = 75(1)

p = 75

Thus, Liam is paid SR 75 per hour.

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2 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

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3 years ago

Pls explain how you figured out both questions

Mariana [72]

Answer:

A=0.125

B=0.125

Step-by-step explanation

for both you would divide 0.5 by 4. you would cut 0.125 off of each side, but two sides together would 0.25

6 0

3 years ago

PLEASE HELP THIS IS DUE TOMORROW

Doss [256]

Answer:

is this the whole assignment because choose a question

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3 years ago

Scale on map is Lin 86 mi if actual distance is 35 mi . Between two cities how far apart on the map are they

Mrac [35]

Answer:

0.41 cm

Step-by-step explanation:

The scale on the map is 1 in 86 mi.

This means that, 1 cm on the map represents 86 miles in real life, or on earth.

Then we're told that in real life, a distance is 35 miles, and how far they are on the map.

If 1 cm equals 86 miles, then we can say that x cm equals 35 miles

1 cm ----> 86

x cm ----> 35

x * 86 = 35 * 1

x = 35 / 86

x = 0.41 cm

Therefore, they must be 0.41 cm farther or closer apart on the map scale.

5 0

2 years ago