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inessss [21]
3 years ago
10

The polynomial 8x2-8x+2-5+x is simplified to 8x2-gx-h. What are the value of g and h?

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0
The answer for G=7 and H=3
Hope this helps!
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Find the area of the composite figure.<br><br> A) 22m<br> B) 26m<br> C) 30m<br> D) 34m
Veronika [31]

Answer:

C is the answer.

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3 years ago
Without graphing predict weather the function y= (1/2)x shows exponential growth or decay. Justify your predictions
Alik [6]

Answer:

The base of the exponential function is 0.5 which is between 0 and 1 and thus this is an exponential decay function.

Step-by-step explanation:

Exponential equations are usually in the form;

y=ab^{x}

where;

a is the initial value, that is the value of y when x is 0,

b is the growth or decay factor and also the base of the exponential function

If b>1, then it is an exponential growth function and the values of y keep getting bigger.

if 0<b<1, then it is an exponential decay function and the y values keep getting smaller as x increases.

In the function given;

y=(\frac{1}{2})^{x}

The base of the exponential function is 0.5 which is between 0 and 1 and thus this is an exponential decay function.

In order to justify our prediction, we can simply obtain the graph of the function and check on how x and y vary.

From the attachment below we can see that the values of y become increasingly smaller as the values of x increases in magnitude which justifies our predictions.

5 0
3 years ago
Evaluate the following expression using the values given:
MrMuchimi
Replace each letter with it's value, so:
= (5*-2) + (-3*2) + 3
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6 0
3 years ago
Read 2 more answers
Help please os of álgebra
kozerog [31]

Answer:

(11, 11)

Step-by-step explanation:

Solve by substitution:

1. set the equations equal to each other

3x-22=-x+22

2. simplify

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3. substitute the value of x into an equation

y=3(11)-22\\y=33-22\\y=11

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ser-zykov [4K]

Answer:

H_1 : \mu  > 24.5

Step-by-step explanation:

From the given information:

The sample size is 28

The population mean is 24.5 (ppb)

The sample mean is 225.3 (ppb)

Thus, the null and the alternative hypothesis can be computed as:

Null hypothesis:

H_o : \mu \le 24.5

Alternative hypothesis:

H_1 : \mu  > 24.5

8 0
3 years ago
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