(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Answer:
10 hours to drive 500 miles
6 hours to drive 300 miles
Step-by-step explanation:
Hi, to answer this we have to calculate the speed rate first:
Speed = distance /time
Speed = 200 miles / 4 hours = 50 miles per hour
So, to find the time for each number of miles:
Time = distance /speed
For 500 miles:
t = 500/50 = 10 hours
For 300 miles
t = 300/50 =6 hours
So, in conclusion:
It will take 10 hours to him drive 500 miles
It will take 6 hours to him drive 300 miles
Answer:
the answer (in my opinion) could be 82 feet per 6.5 minutes
Step-by-step explanation:
(id like to tell you the rest but i can't cause then it would be plagiarism. hope you understand)
36 is 0.9% of 4000.
hope i helped my fellow brainily user
Answer:
4
Step-by-step explanation: