The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Answer:
C
Step-by-step explanation:
(2x + 3)^5 = C(5,0)2x^5*3^0 +
C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5
Recall that
C(n,r) = n! / (n-r)! r!
C(5,0) = 1
C(5,1) = 5
C(5,2) = 10
C(5,3) = 10
C(5,4) = 5
C(5,5) = 1
= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5
= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243
= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243
= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243
If you put in the substitutions it would be 2*2-(2*2*4)+(3*2)-(-4*2)+(2*4).
Simplified further by multiplying it would be 2*2-8+6--8+8
the negative 8 could be simplified further since the negatives cancel out so you'll have 2*2-8+6+8+8.
Then using the order of operations you would multiply the 2's together first to get 4 so you have 4-8+6+8+8.
After that it's simple addition giving you an answer of -26.
I'm not sure if you're looking for the final answer or just the equation with substitutions but there's both.
Answer:
Step-by-step explanation:
1) 792÷ 36=22
2) 1/2 ÷ 3 = 1/6
3) D
4) its 10,00 cause 7.741 x 10 = 77,410
5) the answer in decimal is 60.089
