By the binomial theorem,

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that
12 - 3k = 0 ===> 3k = 12 ===> k = 4
which corresponds to the constant coefficient

Answer:
x = 7
Step-by-step explanation:
The proportion is
14/6 = 21/(3x - 12) Cross Multiply
14*(3x - 12) = 6*21 Remove the brackets and combine
42x - 168 = 126 Add 168 to both sides
42x = 126 + 168
42x = 294 Divide by 42
x = 294/42
x = 7
Answer:
Step-by-step explanation:
One of the easier approaches to graphing a linear equation such as this one is to solve it for y, which gives us both the slope of the line and the y-intercept.
x-3y=-6 → -3y = -x - 6, or 3y = x + 6.
Dividing both sides by 3, we get y = (1/3)x + 2.
So the slope of this line is 1/3 and the y-intercept is 2.
Plot a dot at (0, 2). This is the y-intercept. Now move your pencil point from that dot 3 spaces to the right and then 1 space up. Draw a line thru these two dots. End.
Alternatively, you could use the intercept method. We have already found that the y-intercept is (0, 2). To find the x-intercept, let y = 0. Then x = -6, and the x-intercept is (-6, 0).
Plot both (0, 2) and (-6, 0) and draw a line thru these points. Same graph.
Answer:1
Step-by-step explanation: