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2 years ago

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Kaysha's aunt gave her $5,500 when she was born. Her parents invested it at a rate of 4% interest rate compounded annually. No d

eposits or withdrawals were made. How much money will Kaysha have when she turns 18 years old?

1 answer:

marin [14]2 years ago

3 0

I used this hope it helps:)

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Each participant in a charity lottery is given a unique number. The winner is chosen by picking one number from a bag of red bal

max2010maxim [7]

35 ceremonies for at least come around

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2 years ago

Read 2 more answers

I cant remember this its not a test but i have more questions can someone pleas help

USPshnik [31]

Here, take any points (0, -2) ((1, -6)
Now, slope (m) = -6 - (-2) / 1 - 0 = -6+2 / 1 = -4

Now, y - y1 = m(x - x1)
y - (-6) = -4(x - 1)
y + 6 = -4x + 4
y = -4x - 2

In short, Your Equation would be y = -4x - 2

Hope this helps!

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2 years ago

A cylinder has a base radius of 9m and a height of 14m. What is its volume in cubic m, to the nearest tenths place?

Alik [6]

2544.69m^3 sorry i don’t know to the nearest tenth place :(

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3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

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3 years ago

Pete played in two basketball games he scored 4 fewer points in the second game then he scored in the first he scored 12 in the

Brut [27]

Answer: 16 points

Step-by-step explanation:

12+4=16 You have to add 4 points to the 12 points he got on the second game because in the problem it says that the second game had 4 fewer points then the first.

3 0

3 years ago