1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
4 years ago
14

on Saturday afternoon, six friends agreed to call each other. each friend talked to every other friend once. how many phone call

s were made?
Mathematics
1 answer:
jonny [76]4 years ago
5 0

I think I might be right but you do 6x6 which would be 36.


You might be interested in
Below are summary statistics for the sizes (in acres) of some local vineyards. Using the summary statistics, complete parts (a)
rjkz [21]

Answer:

option B

Step-by-step explanation:

The symmetric distribution have close or approximate values of median and mean. In the given scenario mean is 48.5 and median is 33. We can see that the both values significantly differs. Also, given mean is greater than median(48.5>33) . Thus, the distribution is positively skewed and not symmetrical.

Hence, the distribution is skewed because mean and median significantly differ from each other.

3 0
4 years ago
Which row of Pascal’s triangle would you use to expand (2x 10y)15?
Pepsi [2]

The <em><u>correct answer</u></em> is:

Row 15.

Explanation:

Each row of Pascal's triangle corresponds with the exponent of a binomial. The first row is a binomial to the first power; the second row, to the second power; the third row, to the third power; etc.

For the 15th power, we would want the 15th row of the triangle.

8 0
4 years ago
Read 2 more answers
Which statements are true about the solution of 15 greater-than-or-equal-to 22 + x? Select three options. x greater-than-or-equa
Sidana [21]

Answer:

x \leq  -7

The graph has a closed circle.

–7 is part of the solution.

Step-by-step explanation:

Given

15 \geq 22 + x

Required

Select 3 options from the given list of options

15 \geq 22 + x

Subtract 22 from both sides

15 - 22 \geq 22 - 22+ x

-7 \geq x

Swap positions of the expression; Note that the inequality sign will change

x \leq  -7

This means  <em>x less-than-or-equal-to negative 7</em>

<em></em>

There are two options left to select;

The inequality sign in x \leq  -7 implies that the graph has a close circle.

Inequality signs such as \leq and  \geq signifies a close circle

There is only one option left to select;

Lastly;

Split the expression x \leq  -7 into two

We have:

x < -7 or x = -7

Because x = 7,

Then, -7 is also a part of the solution

3 0
4 years ago
What is the LCM of 24 and 32?
Sphinxa [80]
96 is the answer i beilive
3 0
4 years ago
Read 2 more answers
What is the greatest common factor of 90 and 135?
RSB [31]
  • Answer:

<em>GCF = 45</em>

  • Step-by-step explanation:

<em>90 = 9×10 = 3²×2×5</em>

<em>135 = 45×3 = 9×5×3 = 3²×5×3 = 3³×5</em>

<em>GCF = 3²×5 = 9×5 = 45</em>

6 0
3 years ago
Other questions:
  • Solve the following equation by the Substitution method.<br><br> −5x + y = −2<br><br> x = 2y + 4
    12·1 answer
  • Which methods could you use to calculate the y-coordinate of the midpoint of
    10·1 answer
  • Refer to Explorations in Literature for a complete version of this passage.
    5·2 answers
  • I need help for this question
    6·1 answer
  • when finding the inverse of a relationship , 1st you replace f(x) why y 2nd switch the x's and y's what do you do next.?A) Find
    5·2 answers
  • Abhinav read 14of a book, and if he reads 77 more pages of the book, then Abhinav will complete 69% of the book. How many pages
    5·1 answer
  • HELP ME PLEASEE I NEED HELP IN THIS
    13·1 answer
  • Easy 8th pre-algebra worth ten points each=30 points
    9·1 answer
  • What is the equation of the line that passes through the point (6,-4) and has a<br> slope of - 1/6?
    12·1 answer
  • (no link) this is serious and due at 10:30 please no link thiss is a test
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!