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3 years ago

Find the value of 24/25 divided by 4/5. Show your reasoning

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Answer: 6/5

Step-by-step explanation:

24/25 divided by 4/5 equals 1.2 as a decimal and 6/5 as a fraction.

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A.) weight/(height x height)x 703

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3 years ago

BRAINLIEST <br> Please answer these

zheka24 [161]

3.14 is used for pi.

6. r = $\sqrt{\frac{A}{\pi } }$

14.00

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5.00

8. d = $2 \sqrt{\frac{A}{\pi } }$

23.01

9. r = $\frac{c}{2\pi }$

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10. d $\pi$ = $2 \sqrt{{A}$

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6 0

3 years ago

Susan incorrectly factored the expression below. 12a − 15b + 6 3 (4a + 5b + 3)

hichkok12 [17]

Answer:

3(4a−5b+2)

Step-by-step explanation:

The answer should have originally been 3(4a-5b+2)

3(4a+5b+3)= 12a+15b+9 which is incorrect.

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3 years ago

Is this statement true or false?

Sloan [31]

Answer:

True

Step-by-step explanation:

A down payment is mostly for deposit reasons with insurance. It also let's the landlord know you will be moving in soon. They will use that money for repairs when you move out. You have a chance of getting it pack if they find no damages :D

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3 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$