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SIZIF [17.4K]
3 years ago
14

I need help with this proof i am struggling w geometry...

Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

Your line 4 should have "angle DEC" not "angle EDC". The order of the letters is important. I marked the two angles ABC and DEC in the attached image below. They are alternate interior angles. Because DE || AB, this means the alternate interior angles are congruent.

Since C is the midpoint of EB, this means BC = CE by the definition of the midpoint. Basically EB is cut into two halfs BC and CE which are the same length.

After you establish all of what is mentioned previously, you would use the AAS congruence theorem. AAS stands for Angle Angle Side. One pair of angles are the vertical angles (see line 2). Another pair of congruent angles is the alternate interior angles (line 4). The sides are not between the pairs of angles mentioned. Again check out the attached image for more visual information.

Finally, if we know the triangles are congruent, then the corresponding parts are congruent (CPCTC). That leads to the conclusion that DC = AC.

Edit: it's actually ASA and not AAS because the sides are between the two angles (I was thinking of another diagram earlier)

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Step-by-step explanation:

Here, According to the question,

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= \frac{11!}{3!\times 8! }

= \frac{11\times 10\times 9\times 8!}{6\times 8! }

=\frac{11\times 10\times 9}{6}

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= 165


5 0
3 years ago
Find the particular solution that satifies the differential equation and the initial condition. f"(x) = x2 f'(0) = 8, f(0) = 4
viva [34]

Answer:

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Step-by-step explanation:

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Put X = 0

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Integrate f(x) again with respect to x

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Put X = 0

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5 0
3 years ago
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Step-by-step explanation:

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Marta_Voda [28]

Answer:

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8 0
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