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2 years ago

What is the first step in solving this problem? ⅘ + ½ =

Mathematics

2 answers:

Otrada [13]2 years ago

7 0

Answer:

Find the least common denominator, which is 10.

vova2212 [387]2 years ago

7 0

Setting both fractions up so that they have a common denominator

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What is 90 decreased by 40%?

vaieri [72.5K]

Because it's decreasing, you use the formula (1-x/100)y with x the percentage decreased which is here 40, and y the number decreased which is here 90
So we get
(1-40/100) * 90
(100/100 - 40/100) * 90
60/100 * 90
5400/100
54
So 90 decreased by 40% is 54
Hope this Helps :)

8 0

3 years ago

Is Joan read 74 pages in 4 hours how long will it take her to read 240 pages

kogti [31]

Answer:

It will take her 13 hours

5 0

3 years ago

Find the distance between (-2, 3) & (-7, -7). Round to the nearest tenth.

andre [41]

Answer:

11.2 units

Step-by-step explanation:

From (-7, -7) to (-2, 3) is 5 units horizontally and 10 units vertically. Thus we have a right triangle with sides 5 and 10 respectively. The length of the hypotenuse of this triangle is the distance between (-2, 3) & (-7, -7):

d = √(5² + 10²) = √(25 + 100) = √125 = √25√5, or 5√5.

This is approximately 11.2 units

6 0

3 years ago

Read 2 more answers

Please help?

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

$A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2$

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0

3 years ago

Jackson has 2,000 baseball cards Gabe has 1/10 as many as Gabe how many baseball cards does Gabe have in his collection

Eddi Din [679]

Answer:

200 baseball cards

Step-by-step explanation:

We write the expression:

2000 x 1/10 =

200

4 0

3 years ago