All categories

2 years ago

Choose the law and the formula that would be used to solve the triangle.

Mathematics

1 answer:

Oksana_A [137]2 years ago

4 0

Answer: A^2

Step-by-step explanation:

Angle C + Angle B = Angle A

You might be interested in

30 pts!!!!!!!!!

boyakko [2]

Divide the first one by the second and the answer will be B.

3 0

2 years ago

Read 2 more answers

Help with #1 I can’t get it!!

drek231 [11]

Answer:

for number one, look at the screenshot attached, that should help

Step-by-step explanation:

7 0

2 years ago

Harper knows he is 50 yards from school. The map on his phone shows that the school is 3/4 inch from his current location. How f

yulyashka [42]

Answer:

Harper is 200 yards away from her home if the map shows 3 inches

Step-by-step explanation:

50 yards = 3/4 inch

3 inches = 3/1

3/1 x 4/4 = 12/4

12/4 = 3 inches

50 x 4 = 200

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

6 0

2 years ago

Which expression represents the number

frozen [14]

Answer:

8 + i

Step-by-step explanation:

What you need to simplify this is the following "definitions" of i to different powers.

$i^1=i$

$i^2=-1$

$i^3=i^2*i=-1*i=-i$

$i^4=1$

Now we can sub these in for the various powers of i in our expression:

$6(1)+6(-i)-2(-1)+\sqrt{-1*49}$

Simplifying a bit:

$6-6i+2+\sqrt{i^2*49}$

Since we know that the square root of i-squared is i, and that the square root of 49 is 7, we can get rid of the radial sign as follows:

6 - 6i + 2 + 7i

And the final answer, in a + bi form, is

8 + i

7 0

3 years ago

The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing for

ICE Princess25 [194]

Answer:

76,050 ft²

Step-by-step explanation:

If the area must be rectangular, let L be the length of the side opposite to the creek, and S be the length of the remaining two sides.

The perimeter of the fencing and the area of the pasture are:

$780 = L+2S\\A= LS\\\\L=780-2S\\A=-2S^2+780S$

The value of S for which the derivate of the area function is zero is the length of S that maximizes the area of pasture:

$\frac{dA}{dS}=0=-4S+780\\S= 195\\L=780-(2*195)=390$

The maximum possible area is:

$A_{MAX}=390*195=76,050\ ft^2$

6 0

3 years ago