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Triss [41]
3 years ago
6

Please help me!!! PLEASE!!!!!!!

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

Answer:

no way

Step-by-step explanation:

addison rae? is that u?

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The correct answer would be B
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Solve the following equation <br> 4(3-2x)=15
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Answer:x= -3/8

Step-by-step explanation:

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3 years ago
A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Fin
Debora [2.8K]

Answer:

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error of this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 94% confidence level is, <em>z</em> = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

          =1.88\times\frac{3}{\sqrt{84}}\\\\=0.6154

Thus, the margin of error for the 94% confidence interval is 0.6154.

7 0
3 years ago
Anyone know the answer?? ​
Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54

8 0
2 years ago
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