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3 years ago

I need help!!!!!!!!!

Mathematics

2 answers:

irina1246 [14]3 years ago

7 0

Syntax error wrong question

Sloan [31]3 years ago

5 0

Answer:

Greatest- 2 × 4/9

Then- 1 2/3 × 4/9

Then- 7/7 × 4/9

Lest- 3/4 × 4/9

Step-by-step explanation:

The right hand fraction you are timing by is the same whilst on the left they grow so you order them and dont focus on the times aspect of the question

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Which scenario best matches the linear relationship expressed in the equation y = 32x + 80?

Llana [10]

He has 80 in the bank account and earns 32 each day....where x represents the number of days and y represents the total in the account

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3 years ago

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An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What ra

sdas [7]

Answer:

82.62

Step-by-step explanation:

Mean score (μ) = 80

Standard deviation (σ) = 5

The 70th percentile of a normal distribution has an equivalent z-score of roughly 0.525.

For any given score, X, the z-score can be determined by:

$z=\frac{X-\mu}{\sigma}$

For z = 0.525:

$0.525=\frac{X-80}{5}\\ X=82.62$

A raw score of approximately 82.62 corresponds to the 70th percentile.

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3 years ago

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Help please live or death

iogann1982 [59]

Angle 2 is 143
angle 4 is 37
angle 7 is 143
angle 8 is 37

8 0

3 years ago

HW HELP ASAP PLZZZZZZ

astraxan [27]

Graph 2 should be right because it moves up 1 because of the +1 that is in the parentheses.

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3 years ago

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

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3 years ago