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Pavlova-9 [17]
3 years ago
14

Find the volume of the cone.

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:1/3hπr^2

Step-by-step explanation:

volume of a cone

1/3hπr^2

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sergiy2304 [10]
8-3(2)
8-5
=3
the answer should be 3 after plugging in the variables.

3 0
3 years ago
Need Help please i will mark brainliest when it lets me
timurjin [86]

Answer:it’s the second one

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the lowest common denominator of 1/32 and 2/3
Anuta_ua [19.1K]

Answer:

96

Step-by-step explanation:

The least common denominator or lowest common denominator is the smallest multiple that the denominator (that is the number on the bottom of a fraction) has in common.

Since 32, and 3 have no common factors, one simply has to multiply them to find the least common denominator.

32 * 3 = 96

7 0
3 years ago
P(A) = 0.33, P(A and B) = 0.25, find P(B
motikmotik

Answer:

≈0.76

Step-by-step explanation:

P(A) = 0.33

P(A and B) = 0.25

P(B) = ?

-------------

<u>Probability of two events happening is the product of individual probabilities</u>

  • P(A and B) = P(A)×P(B)

<u>Then to find the probability of one of the events: </u>

  • P(B) = P(A and B) / P(A)
  • P(B) = 0.25 / 0.33 ≈ 0.76
6 0
3 years ago
Given B(17,5), C(11, -3), D-1, 2), and<br> E(x, -6), find the value of x so that BC || DE.
son4ous [18]

Answer:

x=-7

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are the same.
  • Two lines are perpendicular if their slopes are negative reciprocals.
  • And two lines are neither (a.k.a intersecting) if they are neither parallel nor perpendicular.

We want to find the value of x such that \overline{BC}\parallel\overline{DE}.

Therefore, the slopes of BC and DE must be equivalent.

So, let's find the slope of BC first.

BC)

We can use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let B(17, 5) be (x₁, y₁) and let C(11, -3) be (x₂, y₂). Substitute:

m=\frac{-3-5}{11-17}

Subtract:

m=-8/-6=4/3

So, the slope of BC is 4/3.

DE)

Let D(-1, 2) be (x₁, y₁) and let E(x, -6) be (x, y₂). Substitute:

m=\frac{-6-2}{x-(-1)}

We know that the two slopes must be equal. So, the slope of DE must also be 4/3. Substitute 4/3 for m:

\frac{4}{3}=\frac{-6-2}{x-(-1)}

Solve for x. Simplify the right:

\frac{4}{3}=\frac{-8}{x+1}

Cross multiply:

4(x+1)=-8(3)

Multiply on the right:

4(x+1)=-24

Divide both sides by 4:

x+1=-6

Subtract 1 from both sides:

x=-7

So, the value of x is -7.

And we're done!

6 0
3 years ago
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