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Nady [450]
3 years ago
10

Need Help please i will mark brainliest when it lets me

Mathematics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

the 2nd one

Step-by-step explanation:

I asked my brother and he said it was that one

timurjin [86]3 years ago
5 0

Answer:it’s the second one

Step-by-step explanation:

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What is the measure of angle x°?<br> pls answer real quick 20 points
devlian [24]

Answer:

30

Step-by-step explanation:

A triangle has a total degree of 180. We already have 150(from the 60 and the right angle) 180-150 is 30

4 0
2 years ago
Read 2 more answers
Anyone know what these two questions are? the subject is scientific notation
tatiyna

Answer:

1. The negative sign on an exponent means the reciprocal. A negative exponent tells how many times to divide a base number.

2. A positive tells how many times to multiply a base number.

could you also give me a brainliest if I am correct.

thanks!

3 0
3 years ago
Point A is (5, 7).
spin [16.1K]

The coordinate of point B is at (29, -15): Option C is correct.

The formula for calculating the midpoint of two points is expressed as:

M(x, y) = {\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2}}

Given the coordinate points

A is (5, 7).

B is (x, y).

M is (17, -4)

Substituting into the formula to get x and y

17 = 5+x/2

5+x = 34

x = 34 - 5

x = 29

Get the value of y. Similarly;

-4 = 7+y/2

-8 = 7+y

y = -8-7

y = -15

Hence the coordinate of point B is at (29, -15)

Learn more here: brainly.com/question/13989426

5 0
2 years ago
Find each measurement indicated. Round your answers to the nearest tenth.
Crazy boy [7]

Answer:

A

Step-by-step explanation:

Find AB using the Law of Sine:

\frac{AB}{sin(C)} = \frac{AC}{sin(B)}

Thus:

\frac{AB}{sin(40)} = \frac{47}{sin(103)}

Multiply both sides by sin(40)

\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)

AB = \frac{47*Sin(40)}{sin(103)}

AB = 31.0056916 ≈ 31.0 cm (nearest tenth)

6 0
3 years ago
Which statements are true about the expression
bazaltina [42]

Answer:

Wheres the question?

6 0
3 years ago
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