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IrinaVladis [17]
3 years ago
9

How do you solve 13+4x=1-x

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
13+4x=1-x
4x=-12-x (minus 13 from each side)
5x=-12 (add x to each side)
You divide -12 by 5x
-12÷5x=2\frac{2}{5}⇒2.4
x=2.4
laiz [17]3 years ago
3 0
<span>Simplifying 13 + 4x = 1 + -1x
 Solving 13 + 4x = 1 + -1x
 Solving for variable 'x'.
  Move all terms containing x to the left, all other terms to the right.
  Add 'x' to each side of the equation.13 + 4x + x = 1 + -1x + x
 Combine like terms: 4x + x = 5x 13 + 5x = 1 + -1x + x
 Combine like terms: -1x + x = 0 13 + 5x = 1 + 0 13 + 5x = 1
 Add '-13' to each side of the equation. 13 + -13 + 5x = 1 + -13
 Combine like terms: 13 + -13 = 0   0 + 5x = 1 + -13 5x = 1 + -13
 Combine like terms: 1 + -13 = -12 5x = -12 Divide each side by '5'. x = -2.4 Simplifying x = -2.4</span>
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What is the solution to y=6x+25 y=12x-9
prisoha [69]

Answer:

x=17/3, y=59. (17/3, 59).

Step-by-step explanation:

y=6x+25

y=12x-9

--------------

6x+25=12x-9

12x-6x-9=25

6x-9=25

6x=25+9

6x=34

x=34/6=17/3

y=12(17/3)-9=4*17-9=68-9=59

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Leviafan [203]

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Step-by-step explanation: Subtract the biggest number from the smallest. 100-2=98

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SashulF [63]

Answer:

33.275

Step-by-step explanation:

<u>1 step:</u> Difference in brackets

3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}

<u>2 step:</u> 0.75\div\dfrac{1}{3}

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<u>4 step:</u>

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<u>5 step:</u>

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What is the initial value in the function 2x + 3y = 6?
maw [93]
<h2>Explanation:</h2><h2></h2>

The initial value of this function is the y-intercept. We know that the slope-intercept form of the equation of a line is given by:

y=mx+b \\ \\ \\ Where: \\ \\ \\ m:slope \\ \\ b:y-intercept

Writing our equation in slope intercept form:

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