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IrinaVladis [17]
3 years ago
9

How do you solve 13+4x=1-x

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
13+4x=1-x
4x=-12-x (minus 13 from each side)
5x=-12 (add x to each side)
You divide -12 by 5x
-12÷5x=2\frac{2}{5}⇒2.4
x=2.4
laiz [17]3 years ago
3 0
<span>Simplifying 13 + 4x = 1 + -1x
 Solving 13 + 4x = 1 + -1x
 Solving for variable 'x'.
  Move all terms containing x to the left, all other terms to the right.
  Add 'x' to each side of the equation.13 + 4x + x = 1 + -1x + x
 Combine like terms: 4x + x = 5x 13 + 5x = 1 + -1x + x
 Combine like terms: -1x + x = 0 13 + 5x = 1 + 0 13 + 5x = 1
 Add '-13' to each side of the equation. 13 + -13 + 5x = 1 + -13
 Combine like terms: 13 + -13 = 0   0 + 5x = 1 + -13 5x = 1 + -13
 Combine like terms: 1 + -13 = -12 5x = -12 Divide each side by '5'. x = -2.4 Simplifying x = -2.4</span>
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3 years ago
Explain why 1/2 is not equivalent to 2/5.
juin [17]
Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
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7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t
Darina [25.2K]

Answer:

12

Step-by-step explanation:

\sqrt{12} \times\sqrt{12}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0

\sqrt{12}\sqrt{12}=12

=12

7 0
3 years ago
Free 10 points take if u want
kozerog [31]

Answer:

yes pls

Step-by-step explanation:

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3 years ago
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