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nikklg [1K]
2 years ago
15

What's 1/3 of $19.95

Mathematics
2 answers:
ki77a [65]2 years ago
7 0
Answer: 6.65

Explanation: 1995/3= 6.65
gregori [183]2 years ago
7 0

Answer:

6.65

Step-by-step explanation:

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What is the product of 4/7 and 1/6?
jek_recluse [69]

Answer: 0.09523

Step-by-step explanation:

5 0
3 years ago
A mountain in boone county is eroding and losing elevation at a rate of 5% every millennium. if the current elevation is 1,710 m
aliina [53]

Answer: 1,393 meters tall

Step-by-step explanation:

Plug in 1710 meters for the initial amount, 0.05 for the rate of decrease, and 4 millennia for the time elapsed.

y

= a(1–r)t

y

= 1,710(1–0.05)4 Plug in values

y

= 1,710(0.95)4 Subtract

y

= 1,710(0.81450…) Simplify

y

= 1,392.80568… Multiply

Round to the nearest whole number.

1,392.80568… → 1,393

To the nearest whole number, the mountain will be 1,393 meters tall.

3 0
2 years ago
A b and c need solving
algol [13]
Could you zoom out a little maybe? it looks like you cut off something in front of dot
3 0
2 years ago
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
2 years ago
Please awnserrrrrrr quicklyyyyy
jeyben [28]
Pls give this a 5 star rating lol
4 0
2 years ago
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