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sergiy2304 [10]
2 years ago
5

What is the percent of 80 out of 246

Mathematics
2 answers:
ozzi2 years ago
7 0

Answer: 32.5 %

Just divide 80 by 246. You will get .325 . Now multiply that by 100 to get it in percent form. 32.5%

GenaCL600 [577]2 years ago
3 0

Answer:

33%

Step-by-step explanation:

Divide 246 and 80 and move the decimal over twice and round.

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5x+12=44 then value of 5x-12=?​
KATRIN_1 [288]

Answer:

If 5x+12=44 then value of 5x-12 is 20

Step-by-step explanation:

5x + 12 = 44

  • The first step, we have to find the value of x

5x + 12 = 44

5x = 44 - 12

5x = 32

x = 32/5

x = 6.4

  • After that, insert the value of x into 5x - 12

5x - 12 = ...

5 ( 32/5 ) - 12

= 32 - 12

= 20

3 0
3 years ago
Rosario draws the right triangular prism shown here and calculates the volume. She then draws a second right triangular prism in
Tju [1.3M]
The volume of the original prism is given by:
 V1 = (1/2) * (b) * (h) * (H)
 Where,
 b: base of the triangle
 h: height of the triangle
 H: prism height
 The volume of the prism with new dimensions is:
 V2 = (1/2) * (3b) * (3h) * (3H)
 Rewriting:
 V2 = (3 * 3 * 3) * (1/2) * (b) * (h) * (H)
 V2 = (27) * (1/2) * (b) * (h) * (H)
 V2 = (27) * V1
 Answer:
 
The relationship between the volumes of the two prisms is:
 
V2 = (27) * V1
5 0
3 years ago
Read 2 more answers
(x + 2)*(x^2 -2*x+4) - (x^3 -12)
Ivahew [28]

Answer:

  • \large{ \boxed{ \tt{20}}}

- Please see the attached picture for full solution!:)

------------ HappY LearninG <3 -----------

3 0
2 years ago
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
Smith has 12 cans of dog food. He has two dogs and gives 2/3 can of food to each dog in a day. For how many days will his dog fo
Amiraneli [1.4K]

Answer:

He has food for 9 days.

Hence, yes he has enough dog food to last one week.

Step-by-step explanation:

8 0
2 years ago
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