The price of the stereo on sale
is
275 - ( 275x15% ) =
233.75
the comission is 233.75 x 2 % =
233.75 x 2/100 = 4.675
Here are the rules for transformations.
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
f = amount of fliers expected to be mailed in 1 day.
a)
so, she has 5 days to mail those fliers, so
day 1........... 1f mailed out
day 2........... 2f mailed out
day 3........... 3f mailed out
day 4........... 4f mailed out
day 5........... 5f mailed out
so she'll be mailing out a total of 5f fliers, we know whatever "f" is, that total must be at least 850, now, it could be more, no less, could also be 850 exactly, but could also be more, 5f ⩾ 850.
b)

Weight of container =102pounds
<h3>Explaination:</h3>
A shipping container is in the shape of right rectangular prism with the length of the 12feet away, the 8.5 and the height of the 4feet.
The container is completely filled with contants that weigh on average 0.25 pounds of the contents of the container .
Right rectangular prism is a cuboid. Volume of Right rectangular prism=12* 8.5* 4 =408
Cubif feet content destiny=0.25pounds per cubic food
Density = Mass/Volume
= 0.25= weight of contents in the container/Volume of container
= 0.25= weight of contents in container/408
= Weight of contents = container
= 0.25* 408
= Weight of container = 102 pounds
May it helps you