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3 years ago

Which angle is complementary to <4? <2 <1 <6 <3

Mathematics

2 answers:

a_sh-v [17]3 years ago

7 0

The answer would be 3

Hope this helps

Have a great day/night

svlad2 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Clearly <4 and <5 are complementary,

Since <5 is equal to <2 as Vertically Opposite Angles.

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NO LINKS!!!!!! NO RANDOM LETTERS FOR POINTS!!!!!!!!!

melomori [17]

Answer: c (17)

Step-by-step explanation:

you move 7 times first than another 7 and then 3. 7 + 7 + 3 = 17

4 0

3 years ago

Read 2 more answers

What is the reliability of a two-component product if the components are in parallel, with individual reliabilities of 0.95, and

user100 [1]

The reliability of a two-component product if the components are in parallel is 0.99.

In this question,

The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.

A system contains two components that are arranged in parallel, they are 0.95 and 0.80.

Therefore the system reliability can be calculated as follows

⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )

⇒ 1 - (0.05 × 0.20)

⇒ 1 - 0.01

⇒ 0.99

Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.

Learn more about reliability of components here

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6 0

1 year ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$