3 years ago

What is the solution to this linear equation.

Mathematics

1 answer:

icang [17]3 years ago

4 0

-4+3x= 2x +3x +3
-4-3= 2x + 3x -3x
-7 =2x
X= -7/2

You might be interested in

https://lists.office.com/Images/2fce1dfb-919f-4938-aab8-c47f0fc9182d/759a6d77-ea1a-4b50-a9bc-86157c96a662/T14LEZ48DGIIWGRBN9LPBU

Darina [25.2K]

Answer:

54 is th area

Step-by-step explanation:

i have a pitucre your welcome :)

7 0

3 years ago

-6= n/2 - 10 help needed

BARSIC [14]

Answer:

N = 4

Step-by-step explanation:

7 0

3 years ago

Answer key for middle school math with pizzazz! book d d-47

Deffense [45]

Answer:

yea its in the book

Step-by-step explanation:

3 0

3 years ago

At what point of the curve y = cosh(x does the tangent have slope 2?

Dahasolnce [82]

The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44

5 0

3 years ago

Ples help will mark brainliest if 2 answers.

BabaBlast [244]

Answer:

see below

Step-by-step explanation:

Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.

Let's choose x=0 and x=4. Then the corresponding y-values are ...

y = 2·0 = 0 . . . . . point (x, y) = (0, 0)

y = 2·4 = 8 . . . . . point (x, y) = (4, 8)

These are graphed below.

7 0

3 years ago