Answer:
dddddddddddddddddddddddd
Step-by-step explanation:
ssssssssssss
12÷2?
I guess I dunno :/ lel
389,120
It's the first one
All you gotta do is add the value of p with the value of q
![\bf \begin{array}{llll} sin^{-1}[sin(whatever)]= whatever\\\\ cos^{-1}[cos(whatever)]= whatever\\\\ tan^{-1}[tan(whatever)]= whatever \end{array}\\\\ ------------------\\\\ \begin{array}{llll} sin[sin^{-1}(whatever)]= whatever\\\\ cos[cos^{-1}(whatever)]= whatever\\\\ tan[tan^{-1}(whatever)]= whatever \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5E%7B-1%7D%5Bsin%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5E%7B-1%7D%5Bcos%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A------------------%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5Bsin%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5Bcos%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5Btan%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D)
