let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
−2(−9x+5)−4x=2(x−5)−4
Step 1: Simplify both sides of the equation.
−2(−9x+5)−4x=2(x−5)−4
(−2)(−9x)+(−2)(5)+−4x=(2)(x)+(2)(−5)+−4(Distribute)
18x+−10+−4x=2x+−10+−4
(18x+−4x)+(−10)=(2x)+(−10+−4)(Combine Like Terms)
14x+−10=2x+−14
14x−10=2x−14
Step 2: Subtract 2x from both sides.
14x−10−2x=2x−14−2x
12x−10=−14
Step 3: Add 10 to both sides.
12x−10+10=−14+10
12x=−4
Step 4: Divide both sides by 12.
12x
12
=
−4
12
x= -1/3
Step-by-step explanation:
Good luck! Hope this helps! <3
Mixed number form: h = - 1 2/13 Hope that helps :))
Answer:
B. y= 1/2 x - 3
Step-by-step explanation:
base equation: y= mx+ b
slope(m) equation: 
y2= -1 y1= -3
x2= 4 x1= 0
y- intercept: -3
found by taking the y from (0,-3)
Answer:
28
Step-by-step explanation:
7+21=28
a-7=21
