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abruzzese [7]
3 years ago
5

Complete the equation and show which property you used.

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
(3 * 10) * 8 = 3 * (10 * 8)....associative property of multiplication
nikdorinn [45]3 years ago
6 0

(3*10)*8=3*(10*8)

associative property of multiplication

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Consider the equation 2(ax+3)=4x−3(4x+8). For what value of a is there no solution to the equation?
erastovalidia [21]

Answer:

the value of a such that  there is no solution to the equation is a = -4.

Step-by-step explanation:

Let first simplify the expression presented on statement. The equation has no solution if and only if a is eliminated in the process and an absurd is the result (i.e. 0 = 7).

2\cdot (a\cdot x + 3) = 4\cdot x -3\cdot (4\cdot x + 8)

2\cdot a\cdot x +6 = 4\cdot x -12\cdot x -24

2\cdot a \cdot x+6=-8\cdot x-24

2\cdot a\cdot x +8\cdot x = -30

2\cdot (a+4)\cdot x = -30

(a+4)\cdot x = -15

To obtain an absurd, we need that a+4 = 0. Hence, the value of a such that  there is no solution to the equation is:

a = -4

Let prove the certainty of the result. We find that an absurd exist: (a = -4)

0 = -15

5 0
3 years ago
The pencil is 10 cm long and the cup is 8 cm tall. Find the diameter of the base of the cup?
vlada-n [284]
80 because when u do 10 times 8 it’s 80
3 0
2 years ago
Bonsoir pour vais vous m'aider svp développer et réduire l'expression D=(2x+3)²-(x+4)² et factoriser D Svp aider moi
GalinKa [24]

Answer:

d = 3x²+ 4x - 7

C'est la réponse j'espère que ça aide.

5 0
3 years ago
a surf instructor has an initial fee of $12 and charges $8 per hour for lessons. Write a linear equation that represents the tot
Ray Of Light [21]

y = total cost

x = # of hours

$12 + $8x = y

8 0
3 years ago
Find the distance between the points (1, 7) and (10, 1)<br> Please help:)
klio [65]

Answer:

<em>The distance between the points (1, 7) and (10, 1) is 10.82 units</em>

Step-by-step explanation:

<u>Distance between two points </u>

The distance between points A(x,y) B(w,z) can be calculated with the formula:

d=\sqrt{(z-y)^2+(w-x)^2}

We are given the points (1,7) and (10,1), let's use their values and compute the required distance:

d=\sqrt{(1-7)^2+(10-1)^2}

d=\sqrt{(-6)^2+(9)^2}

d=\sqrt{36+81}=\sqrt{117}\approx 10.82

The distance between the points (1, 7) and (10, 1) is 10.82 units

7 0
3 years ago
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