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lions [1.4K]
3 years ago
14

Three tenths times twelve

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

3.6

Step-by-step explanation:

0.3x12=3.6

Because you know that 12x3=36, so 12x0.3=3.6!

Good luck!

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Which point is located at -0.135? <br> A<br> B <br> C or <br> D
Sergeu [11.5K]
D as you can see on the number line d is 1/3 of the way to -2
6 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
A clothing shop is offering a
KatRina [158]

Step-by-step explanation:

the correct answer is

discount price=(original price)(1-0.12)

let's suppose the original price is $10 then the discounted price will be

(10)(1-0.12)=10(.88)=$8.8

4 0
3 years ago
Paula bought a ski jacket on sale for $5 less than half its original price. She paid $85 for the jacket. What was the original p
NikAS [45]

Answer:

85+5=90x2=$180

Step-by-step explanation:

3 0
3 years ago
2x+3y=11<br> Solve for x and y
irga5000 [103]
To solve this equation you have to isolate one variable, first we will solving for x, then for y.

Solving for x

2x+3y=11

2x=11-3y

\boxed{\boxed{x=\frac{11}{2}-\frac{3}{2}*y}}

Solving for y

2x+3y=11

3y=11-2x

\boxed{\boxed{y=\frac{11}{3}-\frac{2}{3}*x}}
6 0
3 years ago
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