The graph of an absolute value function y=a|x| includes the points (1,6) and (-1,6)
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Let x represent the larger number.
1/(x -28) +4/x = 1/6
Multiplying by the product of denominators, we have
6x +24(x -28) = x(x -28)
In standard form, this is
x^2 -58x +672 = 0
(x -42)(x -16) = 0
The two numbers are (-12 and 16) or (14 and 42).
1/(x -28) +4/x = 1/6
Multiplying by the product of denominators, we have
6x +24(x -28) = x(x -28)
In standard form, this is
x^2 -58x +672 = 0
(x -42)(x -16) = 0
The two numbers are (-12 and 16) or (14 and 42).