Suppose f(x)= x^2 fins the graph of f(x-1)
1 answer:
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the complete question in the attached figure
1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.
P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512
2) what is the probability that the first victim picks SOMEONE? ANYONE?
P=(1/5)=0.20 ---------------- > 20%
3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)=0.04 --------------> 4%
4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%
5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512
6) Once you find all those probabilities, what rule would apply?
the probability is given by (1/5)^n
n=number of victims that pick the same person---------> in this problem = 9
P=(1/5)^9= 0.000000512
Each bike has two tires, while each quad has four tires. Therefore the number of tires Ruby has to other is given by the number of tires used by the bikes added by the number of tires used by the quads. This is shown on the expression below: