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Serhud [2]
3 years ago
8

The length of a rectangle is 2 cm longer than its width.

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0
In a rectangle, there will be two sets of equal lengths:
56 = 2(x) + 2(x + 2)
56 = 2x + 2x + 4
56 = 4x + 4
52 = 4x
13 = x
Width = 13cm
Length = 15cm
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earnstyle [38]
The answer is the the second one
3 0
3 years ago
3x +y = -2x+8
soldier1979 [14.2K]

Answer: c) -4

Step-by-step explanation:

Get the variables on one side of 3x+y=-2x+8 and the constants on another side:

3x+y=-2x+8

(3x+y)+2x=(-2x+8)+2x

5x+y=8

Now, multiply 5x+y=8 by -2:

-2(5x+y=8)

-10x-2y=-16

Add this equation to -3x+2y=-10:

(-10x-2y=-16)+(-3x+2y=-10)

-13x=-26

x=2

Plug x=2 into -3x+2y=-10:

-3(2)+2y=-10

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Therefore, (2, -2) is the solution to the system of equations, so xy=(2)(-2)=-4

5 0
3 years ago
What quadrant would the ordered pair (–4,–6) fall in?
sveta [45]
QUADRANT 3 IS the right answer
3 0
4 years ago
Read 2 more answers
360 km is 24% of blank kilometers
Ede4ka [16]

Answer:

86.4km

Step-by-step explanation:

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4 0
3 years ago
Let A and B be subsets of a universal set U and suppose n(U)=400, n(A)=135, n(B)=80, and n(A n B)=60. Find the number of element
Alexxandr [17]
Use A' for A complement, etc. and n = intersection ∩.
n(A' n B')
=n(A u B)'   by the de Morgan's law
=nU-n(nA+nB-n(AnB))     n(A u B) = nA + nB - n(AnB)  and nX'=nU-nX
=400-(135+80-60)
=400-155
=245
5 0
3 years ago
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