I need to answer two questions in order to ask a question. sorry that i’m stupid and have no idea how to do this
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Dan isn’t correct it’s either c or d
The given data is the following:
Student Trial 1 Trial 2 Trial 3 Average
----------- -------- -------- -------- ------------
1 66.0 66.5 68.5 67.0
2 67.5 64.0 70.5 67.3
3 60.3 60.5 60.5 61.0
4 55.0 58.0 59.0 57.3
Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0 Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3 Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604 Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3 Correct
Answer: Student 3
