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Studentka2010 [4]

2 years ago

11

In the figure, AB¯¯¯¯¯ is parallel to DE¯¯¯¯¯ .

2 answers:

lisov135 [29]2 years ago

6 0

To answer this problem, let us first discuss what is a similar triangle:
Similar triangle is defined as having two or more triangles that have<span> all corresponding angles that are equal and all corresponding sides that are proportionate. It does not matter what direction the triangles are facing. Their size does not matter as long as each side is proportionate.
In figure shown, it is observed that the the corresponding angles are equal and sides are proportionate. Thus,</span><span>Triangle ABC and triangle DEC are <u>SIMILAR</u>.</span>

Lynna [10]2 years ago

5 0

Answer:

It's A

Step-by-step explanation:

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Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths

Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e $(base)^2 + (Height)^2 = (Hypotenuse)^2$

For the given Lengths 7, 40 and 41

We need to check if

$7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2$

$Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681$

That means, $\\ 7^2 + 40^2 \neq 41^2$

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

$12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2$

Therefore given sides 12,16 and 20 can be the sides of right triangle.

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