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3 years ago

-k+ 3k Combining like terms and distributing

1 answer:

8 0

2k Is the answer bc k becomes -k multiply k and 3 multiply k and 1, the k just gets copied along the answer is k then 3*k evaluates to 3k -k+3*k evaluates to 2k

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4/5 divided by 1/3 ??

DochEvi [55]

Answer:

2.4

Step-by-step explanation:

3 0

3 years ago

Length = 2 feet, width = 15 inches, height = 8 inches V= _____________

I am Lyosha [343]

Volume = length * width ( aka base ) * height

2 feet = 24 inches.

24*15*8=2880 inches.

6 0

3 years ago

Read 2 more answers

Formulate the situation as a system of inequalities. (Let x represent the number of dinghies the company can manufacture and y r

kirill [66]

Answer:

x (smallest to largest) = 0,45 ,55

y (smallest to largest) = 0,10,40

Step-by-step explanation:

(hours) Dinghy Rowboat Labor Available

Metal Work 2 3 120

Painting 2 2 110

Let x represent the number of dinghies the company can manufacture and y represent the number of rowboats.

So, total hours for metal work = $2x+3y$

So, total hours for Painting = $2x+2y$

So, equation becomes:

$2x+3y\leq 120$

$2x+2y\leq 110$

$x\geq 0$

$y\geq 0$

Plot the inequalities

Refer the attached figure

So, the vertices of the feasible region are (0,40),(45,10) and (55,0)

So, x values are 0 , 45 and 55

x represents the number of dinghies

So, x (smallest to largest) = 0,45 ,55

y values are 40,10,0

y represent the number of rowboats.

So, y (smallest to largest) = 0,10,40

3 0

3 years ago

May somebody please help me with this please

elixir [45]

P = A / (1 + rt)
P = 80000 / (1 + (0.09)(0.5))

P = $ 76,555.02

7 0

3 years ago

A water tank is being filled by pumps at a constant rate. The volume of water in the tank V, in gallons, is given by the equatio

mamaluj [8]

Answer:

65 gallons per minute

Step-by-step explanation:

The total volume of the tank at any given time is given by the equation:

V(t) = 65t + 280

In order to find the rate of change of volume, we can simply differentiate this equation with respect to time. This will give us the rate of change of the volume or the rate at which water is being pumped into the tank.

Differentiating the above equation we get:

V'(t) = 65

So we can see that the rate at which water is being pumped into the tank is 65 gallons per minute

7 0

3 years ago