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Gnoma [55]
3 years ago
11

Help help plz about to fail

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0
I believe the answer that you are looking for is (1,4) although I cannot see the full graph, so I do not know. If you start a point R and move 4 units to the left and 3 units up, you come to the point: (1,4).
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The cost in dollars of making x items is given by the function C(x) = 10x + 500. a. The fixed cost is determined when zero items
Brilliant_brown [7]

Answer:

a. $500

b. $250

Step-by-step explanation:

a. For zero items produced, cost will be-

C(0) = 10(0) + 500 = 0 + 500 = 500

b. For zero items produced, cost will be-

C(25) = 10(25) + 500 = 250 + 500 = 750

c. If C(x)_{max} = 1500

10x + 500 = 1500\\10x = 1000\\x = 100

∴ domain for cost function will be [0,100] and range will be 100

7 0
3 years ago
Find the slope of the line that goes through the given points.<br> (0,8) and (- 4,0)
Ronch [10]

Answer:

slope = 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 8) and (x₂, y₂ ) = (- 4, 0)

m = \frac{0-8}{-4-0} = \frac{-8}{-4} = 2

6 0
3 years ago
Read 2 more answers
Show all work to identify the asymptotes and zero of the function f of x equals 5 x over quantity x squared minus 25.
Lorico [155]

Answer:

  • asymptotes: x = -5, x = 5
  • zero: x = 0

Step-by-step explanation:

The function of interest is ...

  f(x)=\dfrac{5x}{x^2-25}=\dfrac{5x}{(x-5)(x+5)}

The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5

__

The zeros are found where the numerator is zero. It will be zero for x = 0.

The asymptotes are x=-5, x=5; the zero is x=0.

4 0
3 years ago
How do you factor this? x^{2} + 5 x- 9 = ?
Oksanka [162]
x^2+5x-9\\\\a=1;\ b=5;\ c=-9\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot1\cdot(-9)=25+36=61 > 0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{61}\\\\x_1=\dfrac{-5-\sqrt{61}}{2\cdot1}=\dfrac{-5-\sqrt{61}}{2}\\\\x_2=\dfrac{-5+\sqrt{61}}{2\cdot1}=\dfrac{-5+\sqrt{61}}{2}\\\\x^2+5x-9=\left(x-\dfrac{-5-\sqrt{61}}{2}\right)\left(x-\dfrac{-5+\sqrt{61}}{2}\right)
6 0
3 years ago
Evaluate 82.5÷0.25 express the answer in standard form​
Marina86 [1]

Answer:

330

Step-by-step explanation:

hope this helps

follow me for more answers

can i have Brainliest

8 0
3 years ago
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