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lidiya [134]
2 years ago
5

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present

age of the mother?.
Mathematics
1 answer:
natali 33 [55]2 years ago
7 0

An equation is formed of two equal expressions. The present age of the mother is 45 years.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the son's present age be represented by x. Therefore, we can represent the statement "mother is twice as old as her son" as,

Son's present  age = x

Mother's present age = 2 × son's age = 2x

Also, 20 years ago, the age of the mother was 10 times the age of the son. Therefore, we can write,

Son's age 20 years ago = x - 20

Mother's age 20 years ago = 2x - 20

Mother's age 20 years ago = 10 × Son's age 20 years ago

2x- 20 = 10 × (x - 20)

2x - 20 = 10x - 200

-20 + 200 = 10x - 2x

180 = 8x

x = 180/8

x = 22.5

Now, the present age of the mother is,

Mother's present age = 2x =  2 × 22.5 = 45

Hence, the present age of the mother is 45 years.

Learn more about Equation here:

brainly.com/question/14686792

#SPJ4

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