All categories

2 years ago

Could ya help me plz

Mathematics

1 answer:

Mademuasel [1]2 years ago

4 0

Answer:

Y is 55

X is 70

Step-by-step explanation:

Angle on straight lines adds to 180. So, 180 - 125 =55. If base angles are equal, to find x, add all vales of y and take away from 180. Angle in triangle add to 180.

55 + 55 =110

180 - 110 =70

You might be interested in

Simplify the radical expression. Please explain how you got your answer. √25/4

astra-53 [7]

√25/4=5/2 because 5/2 times 5/2 equal 25/4. Hope it help!

6 0

3 years ago

Match the conditional statement p→q, the converse q→p, the inverse ~p→~q, and the contrapositive ~q→~p in words.

Yuri [45]

For the text answers:

conditional - If 2 lines are supplementary then the measure of the angles sum is 180

converse - If the measure if the angle sum is 180 then the 2 lines are supplementary

inverse - If 2 lines are not supplementary then the measure if the angle sum is not 180

contrapositive - If the measure if the angle sum is not 180 then 2 lines are not supplementary.

answer to the picture one:

conditional - If you do all your math homework then you will do well on the test.

converse - If you do well on the test then you do all your math homework

inverse - If you do not do all your math homework then you will not do well on the test.

contrapositive - If you do not well on the test then you did not do all your math homework

5 0

3 years ago

V = e^3 when e = 7 please help me

Nuetrik [128]

Answer:

343

Step-by-step explanation:

7^3=7×7×7=343

If e is equal to 7 just multiply 7 by 7 and then multiply that answer by 7 to find 7 to the power of 3.

7 0

3 years ago

Question 11 plz, really need help

madam [21]

Answer:

ummm hold on im trying to figure it out sorry might take long

7 0

3 years ago

Read 2 more answers

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

3 years ago