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Amanda [17]
3 years ago
9

Teeth rented a truck for one day. There was a base fee of $18.95,and there was an additional charge $.99 for each mile driven. K

eith had to pay $155.57 When He returned. How many miles did he drive a truck
Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer:

138 miles.

Step-by-step explanation:

This can be written in an equation as y=($0.99)x + ($18.95), where the initial value is $18.95 (same as a y -intercept), and then the slope would be $0.99 times x, the number of miles driven.

In this case, you then calculate:

$155.57 = ($0.99) × X + $18.95

Subtract the $18.95 from both sides to get:

$136.62 = ($0.99) X

Divide $0.99 from both sides to get:

138 = x

I also liked this question because the guy who rented the truck was named Keith.

Marizza181 [45]3 years ago
6 0

Answer:

138 miles

Step-by-step explanation:

You would have to find the difference between $18.95 and $155.57. When you find the total which is $136.62, you would need to divide it by $0.99. That is what will give you the number of miles that Teeth drove.

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Step-by-step explanation:

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Step-by-step explanation:

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The hypotenuse of a right angled triangle is 2√13 cm . If the smaller side is increased by 2 cm and the larger side is increased
White raven [17]

<em><u>Statement:</u></em>

The hypotenuse of a right angled triangle is 2√13 cm. If the smaller side is increased by 2 cm and the larger side is increased by 3 cm, the new hypotenuse will be √117 cm.

<em><u>To find out:</u></em>

The length of the larger side of the right angled triangle.

<em><u>Solution:</u></em>

Let us consider x as the smaller side and y as the larger side.

Then, in the right angled triangle,

x² + y² = (2√13)² ...(I) [By Pythagoras Theorem]

Now, if the smaller side is increased by 2 cm, then the smaller side will be (x + 2).

And if the larger side is increased by 3 cm, then the larger side will be (y + 3).

Then, in the new right angled triangle,

(x + 2)² + (y + 3)² = (√117)² [By Pythagoras Theorem]

or, x² + 2 × 2 × x + 2² + y² + 2 × 3 × y + 3² = (√117)²

or, x² + 4x + 4 + y² + 6y + 9 = (√117)²

or, x² + y² + 4x + 6y + 13 = (√117)²

Now, put the value of x² + y² from equation (I),

or, (2√13)² + 4x + 6y + 13 = (√117)²

or, (2 × 2 × √13 × √13) + 4x + 6y + 13 = (√117 × √117)

or, 52 + 4x + 6y + 13 = 117

or, 4x + 6y = 117 - 52 - 13

or, 4x + 6y = 52

or, 4x = 52 - 6y

or, x = \frac {(52 - 6y)}{4} ...(II)

Now, put the value of x of equation (II) in (I),

x² + y² = (2√13)²

or, \frac {(2704-624y +36y²)}{16} + y² = 52

or, \frac {(2704-624y +36y² + 16y²)}{16}= 52

or, 52y²-624y + 2704 = 52 × 16

or, 52y² - 624y + 2704 - 832 = 0

or, 52y² - 624y + 1872 = 0

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So, the length of the larger side is 6 cm.

<em><u>Answer:</u></em>

6 cm

Hope you could understand.

If you have any query, feel free to ask.

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