Answer:
<u>40 sq. ft.</u>
Step-by-step explanation:
Given :-
Volume = 160 cu. ft.
Height = 4 ft.
To Find :-
Base Area
Relation :-
Volume = Base Area x Height
Solving :-
Base Area = 160/4
= <u>40 sq. ft.</u>
Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
<h3><u>
Solution:</u></h3>
Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
Step-by-step explanation:
step 1. properties of equality have an "=" in the equation.
step 2. properties of inequality have a <, <=, >=, or a >.