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svet-max [94.6K]
3 years ago
10

Given that y and x are directly proportional and y=22 when x=6, find the value of y when x=15.

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

y = 55

Step-by-step explanation:

Hi,    

Remember: if y and x are directly proportional, you could write a ratio with those values, as follows:

y:x becomes 22:6

You can write an equation with the new value:  

y:15 = 22:6

Now solve by cross multiplication. Imagine that those ratios are fractions:

y/15 = 22/6

y*6=15*22

6y=330

y=55

The value of y is 55 when x is 15.

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of the 200 seniors graduating, 50 took an art class while in highschool and 99 were in the band . Only 30 of the students who to
elena-s [515]

Answer:

69 or 71, read below for details.

Step-by-step explanation:

This is unfinished, but I'll answer to my best ability.

200 seniors graduated

99 in band

30 students in art were NOT in band.

I assume the question here is either how many students were in band and art, which would be 69 as 99 - 30 = 69.

If the question is how many students didn't take any electives, the answer is 200 - 99 - 30 = 71.

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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Aneli [31]
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Sec s = 1.6948
Anastaziya [24]
That'd be true only if the value of "s" is the exact same one for both
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then solving for "s"
thus

\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
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\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
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