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WITCHER [35]
3 years ago
11

Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x+3) and (x+12)

Mathematics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer:

The value of x is -3 and -12 which make a polynomial equal to zero.

Step-by-step explanation:

Given : The factors of the polynomial were (x+3) and (x+12).

To find : Which values of x would make a polynomial equal to zero.

Solution :

The factors of the polynomial were (x+3) and (x+12).

To find the value of x we equation the product of factors equate to zero.

i.e. (x+3)(x+12)=0

(x+3)=0\text{ (or) }(x+12)=0

x=-3\text{ (or) }x=-12

So, The value of x is -3 and -12 which make a polynomial equal to zero.

Alex Ar [27]3 years ago
3 0

Answer:

A product of factors is zero if and only if one or more of the factors is zero.  That is, if ab = 0, then either a = 0 or b = 0 (or both).

Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both.  (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.

Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.

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CAN SOMEONE MULTIPLY THIS PLEASE, ITS URGENT
____ [38]

Let's factorise it :

\: {\qquad  \dashrightarrow \sf   ( {x}^{3}   -  5)(x + 3)  }

\: {\qquad  \dashrightarrow \sf    {x}^{3} (x + 3) + [-5(x + 3)]  }

Using Distributive property we get :

\: {\qquad  \dashrightarrow \sf    {x}^{3} +  {3x}^{3}   + ( - 5x - 15)  }

\: {\qquad  \dashrightarrow \sf    {x}^{3} +  {3x}^{3}   - 5x - 15 }

\: {\qquad  \dashrightarrow \sf    4{x}^{3}  - 5x - 15 }

⠀

Therefore,

\: {\qquad  \dashrightarrow \sf   ( {x}^{3}   -  5)(x + 3)   =4{x}^{3}  - 5x - 15}

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