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Studentka2010 [4]
2 years ago
12

I NEED HELP!!!!! ASAP!!!!!

Mathematics
1 answer:
zloy xaker [14]2 years ago
5 0

Answer: 127 11/12

Step-by-step explanation:

1. 1/2 + 3/4 = 2/3

Change 1/2 by by multiplying by 2 to get a common denominator of fourths.

2/4 + 3/4 = 2/3?

5/4 = 2/3?

no

2. 5/8 - 1/4

Change 1/4 by by multiplying by 2 to get a common denominator of eighths.

5/8 - 2/8 = 3/8?

3/8 = 3/8 ?

yes

3/8 x 10 = 30/8

3. 4/5 +7/10 = 1 1/2

Change 4/5 by multiplying by 2 to get a common denominator tenths.

8/10 + 7/10 = 1 1/2?

15 /10 = 1 1/2?

yes

1 1/2 x 10 = 25

4. 2 1/3 - 1 5/6 = 1/6

Change 1/3 by multiplying by 2 to get a common denominator sixths.

2 2/6 - 1 5/6 = 1/6?

3/6 = 1/6

no

100 -2/3 - 1/6 + 30/8 + 25

multiply the thirds by 8. Sixths by 4. Eighths by 3 to get a common denomonator of 24ths.

100 - 16/24 - 4/24 + 90/ 24 + 25 = 125 70/24

create mixed number

127 22/24

reduce

127 11/12

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A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio
Klio2033 [76]

Answer:

  • k = 0.032
  • P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

  • k = 0.032
  • P0 = 131.836
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3 years ago
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