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3 years ago

You receive $45 profit from a car wash after $300 in sales. What percent was your profit?

Mathematics

2 answers:

Strike441 [17]3 years ago

7 0

<h2>Answer:</h2>

<h3>Step-by-step explanation:</h3>

You receive 45\$ profit from a car wash after 300\$ in sales.

so,

percentage of profit

$\sf{\dfrac{45}{300}×100 }$

$\sf{\dfrac{45}{\cancel{300}}×\cancel{100 }}$

$\bold{\dfrac{45}{3} }$

$\green{ 15\% }$

kirza4 [7]3 years ago

3 0

Answer:

15%

Step-by-step explanation:

Find the percent of profit by dividing 45 by 300:

45/300

= 0.15

So, the percent profit was 15%

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The girls and boys' basketball teams sponsored a car wash that made $109. There were twice as many girls as

V125BC [204]

Answer:

Boys - 36$ 33 cents

Girls - 72$ 67 cents

Step-by-step explanation:

Boys x

Girls 2x

Total 109

2x+x=109

3x=109/:3

X=36,3333

Boys x =36$ 33c

Girls 2x= 72,666= 72$ 67c

7 0

3 years ago

Suppose a large shipment of telephones contained 21% defectives. If a sample of size 498 is selected, what is the probability th

grandymaker [24]

Answer:

$P(-3\% < x < 3\%) = 0.901$

Step-by-step explanation:

Given

$p = 21\%$

$n = 498$

Required

$P(-3\% < x < 3\%)$

First, we calculate the z score

$z = \sqrt{p * (1 - p)/n}$

$z = \sqrt{21\% * (1 - 21\%)/498}$

$z = \sqrt{21\% * (79\%)/498}$

$z = \sqrt{0.1659/498}$

$z = \sqrt{0.000333}$

$z = 0.0182$

So:

$P(-3\% < x < 3\%) = P(-3\%/0.0182 < z$

$P(-3\% < x < 3\%) = P(1.648 < z$

From z probability, we have:

$P(-3\% < x < 3\%) = 0.901$

6 0

3 years ago

Which equation could represent the relationship shown in the scatter plot?

horsena [70]

Answer:

Step-by-step explanation:

Use POE, none of the answer makes any sense

8 0

3 years ago

Read 2 more answers

Let y 00 + by0 + 2y = 0 be the equation of a damped vibrating spring with mass m = 1, damping coefficient b > 0, and spring c

stira [4]

Answer:

Step-by-step explanation:

Given that:

The equation of the damped vibrating spring is y" + by' +2y = 0

(a) To convert this 2nd order equation to a system of two first-order equations;

let y₁ = y

y'₁ = y' = y₂

So;

y'₂ = y"₁ = -2y₁ -by₂

Thus; the system of the two first-order equation is:

y₁' = y₂

y₂' = -2y₁ - by₂

(b)

The eigenvalue of the system in terms of b is:

$\left|\begin{array}{cc}- \lambda &1&-2\ & -b- \lambda \end{array}\right|=0$

$-\lambda(-b - \lambda) + 2 = 0 \ \\ \\\lambda^2 +\lambda b + 2 = 0$

$\lambda = \dfrac{-b \pm \sqrt{b^2 - 8}}{2}$

$\lambda_1 = \dfrac{-b + \sqrt{b^2 -8}}{2} ; \ \lambda _2 = \dfrac{-b - \sqrt{b^2 -8}}{2}$

(c)

Suppose $b > 2\sqrt{2}$ , then λ₂ < 0 and λ₁ < 0. Thus, the node is stable at equilibrium.

(d)

From λ² + λb + 2 = 0

If b = 3; we get

$\lambda^2 + 3\lambda + 2 = 0 \\ \\ (\lambda + 1) ( \lambda + 2 ) = 0\\ \\ \lambda = -1 \ or \ \lambda = -2 \\ \\$

Now, the eigenvector relating to λ = -1 be:

$v = \left[\begin{array}{ccc}+1&1\\-2&-2\\\end{array}\right] \left[\begin{array}{c}v_1\\v_2\\\end{array}\right] = \left[\begin{array}{c}0\\0\\\end{array}\right]$

$\sim v = \left[\begin{array}{ccc}1&1\\0&0\\\end{array}\right] \left[\begin{array}{c}v_1\\v_2\\\end{array}\right] = \left[\begin{array}{c}0\\0\\\end{array}\right]$

Let v₂ = 1, v₁ = -1

$v = \left[\begin{array}{c}-1\\1\\\end{array}\right]$

Let Eigenvector relating to λ = -2 be:

$m = \left[\begin{array}{ccc}2&1\\-2&-1\\\end{array}\right] \left[\begin{array}{c}m_1\\m_2\\\end{array}\right] = \left[\begin{array}{c}0\\0\\\end{array}\right]$

$\sim v = \left[\begin{array}{ccc}2&1\\0&0\\\end{array}\right] \left[\begin{array}{c}m_1\\m_2\\\end{array}\right] = \left[\begin{array}{c}0\\0\\\end{array}\right]$

Let m₂ = 1, m₁ = -1/2

$m = \left[\begin{array}{c}-1/2 \\1\\\end{array}\right]$

∴

$\left[\begin{array}{c}y_1\\y_2\\\end{array}\right]= C_1 e^{-t} \left[\begin{array}{c}-1\\1\\\end{array}\right] + C_2e^{-2t} \left[\begin{array}{c}-1/2\\1\\\end{array}\right]$

So as t → ∞

$\mathbf{ \left[\begin{array}{c}y_1\\y_2\\\end{array}\right]= \left[\begin{array}{c}0\\0\\\end{array}\right] \ \ so \ stable \ at \ node \ \infty }$

5 0

3 years ago

If 3 employees took 3/4 of a pie Home how much pie did wacho employee receive

Aleksandr [31]

Answer:

2 1/4 pies or 2.25

Step-by-step explanation:

3/4 = .75 = 75%

a whole pie is 100% or 1

3 took 3/4

3 x .75 = 2.25

lets break this answer down

if 1 is a whole pie then that would mean 2 would equal 2 whole pies

now with the left over .25 it would be 25% so 2 1/4

3 0

2 years ago