All categories

3 years ago

You receive $45 profit from a car wash after $300 in sales. What percent was your profit?

Mathematics

2 answers:

Strike441 [17]3 years ago

7 0

<h2>Answer:</h2>

<h3>Step-by-step explanation:</h3>

You receive 45\$ profit from a car wash after 300\$ in sales.

so,

percentage of profit

$\sf{\dfrac{45}{300}×100 }$

$\sf{\dfrac{45}{\cancel{300}}×\cancel{100 }}$

$\bold{\dfrac{45}{3} }$

$\green{ 15\% }$

kirza4 [7]3 years ago

3 0

Answer:

15%

Step-by-step explanation:

Find the percent of profit by dividing 45 by 300:

45/300

= 0.15

So, the percent profit was 15%

You might be interested in

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xe^y + ye^z +

LUCKY_DIMON [66]

Answer:

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

Step-by-step explanation:

We need to find the directional derivative of the function at the given point in the direction of the vector v.

$f(x, y, z)=xe^{y} + ye^{z} + ze^{x}$ ,point (0, 0, 0) and $v=$

By Theorem: If f is a differentiable function of x , y and z , then f has a directional derivative for any unit vector $\overrightarrow{v} =$ and

$D_{\overrightarrow{u}}f(x,y,z)=f_{x}(x,y,z)u_1+f_{y}(x,y,z)u_2+f_{z}(x,y,z)u_3$

where $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

since, $v=$

then $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

$\overrightarrow{u}=< \frac{6}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{-3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}} >$

$\overrightarrow{u}=< \frac{6}{\sqrt{54}},\frac{3}{\sqrt{54}},\frac{-3}{\sqrt{54}} >$

The partial derivatives are

$f_{x}(x,y,z)=e^{y}+ze^{x}$

$f_{y}(x,y,z)=xe^{y}+e^{z}$

$f_{z}(x,y,z)=ye^{z}+e^{x}$

Then the directional derivative is

$D_{\vec{u}}f(x,y,z)=(e^{y}+ze^{x})(\frac{6}{\sqrt{54}})+(xe^{y}+e^{z})(\frac{3}{\sqrt{54}})+(ye^{z}+e^{x})(\frac{-3}{\sqrt{54}})$

so, directional derivative at point (0,0,0)

$D_{\vec{u}}f(0,0,0)=(e^{0}+0e^{0})(\frac{6}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{3}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{-3}{\sqrt{54}})$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}+\frac{3}{\sqrt{54}}+\frac{-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6+3-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

3 0

4 years ago

Work out the value of 8^2+4^3, 5^3-7^2

liberstina [14]

Answer:

302

Step-by-step explanation:

8 0

2 years ago

12.

slega [8]

in a week 7

in W weeks ....W*7 this is the answerwer:

Step-by-step explanation:

7 0

4 years ago

OK, I REALLY NEED ALL OF THIS DONE SOON!

Rudik [331]

Answer: 1. 140 times

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

It takes 8 people to pull a 16 ton truck. How many people would it take take to pull a 60 ton truck? I got 30 people am I right?

kiruha [24]

8 people pull a 16 ton truck
we can make that a proportion
8:16
which can be reduced to
1:2

that means 1 person can pull 2 tons

to pull a 60 ton truck, you would have a proportion of
x: 60 = 1:2

cross multiply and you get

60 = 2x
x = 30

yes, you're right!

6 0

4 years ago