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RoseWind [281]
3 years ago
6

Create a graph of the combined function h(x)=f(x)+g(x) in which f(x)=x+6​

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

Step-by-step explanation:

You must share g(x).

Working with what you've already shared:

h(x) = f(x) + g(x)

      = x + 6 + g(x)

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Write a quadratic function in vertex form whose graph has the vertex
ELEN [110]

Answer:

y = \frac{1}{2}(x - 5)² - 2

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (5, - 2), thus

y = a(x - 5)² - 2

To find a substitute (7, 0) into the equation

0 = a(7 - 5)² - 2

0 = 4a - 2 ( add 2 to both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{2}{4} = \frac{1}{2}

y = \frac{1}{2} (x - 5)² - 2 ← in vertex form

4 0
2 years ago
What is the y-intercept of the line whose equation is y=-x-2?
dalvyx [7]

Answer:

-2

Step-by-step explanation:

If we have an equation of the form y = mx +b then the y-intercept is b.

So now here we have y =-x - 2. Therefore b = -2 and we conclude the y-intercept is -2.

8 0
3 years ago
Read 2 more answers
Find the mode of the following list of points earned on a 16 point quiz given during a finance class.
koban [17]

Answer:

7

Step-by-step explanation:

The mode is the most repeated number in the data set. In this case, that is 7 because it's repeated 3 times.

8 0
3 years ago
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Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
In rectangle PQRS, PR = 18x – 28 and QS = x + 380. Find the value of x and the length of each diagonal.
Flauer [41]

Diagonals of a rectangle are congruent.


18x - 28 = x + 380


Solving for x, I get 17.


So, x = 17.


PR = 18x - 28


PR = 18(17) - 28


PR = 278


QS = x + 380


QS = 17 + 380


QS = 397

5 0
2 years ago
Read 2 more answers
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