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yarga [219]
3 years ago
14

ASAP PLEASE!!!! What is an equation for the line with slope 2/3 and y-intercept 9?

Mathematics
2 answers:
Ainat [17]3 years ago
7 0
Y=2/3x+9 the answer is C
Sergio [31]3 years ago
4 0

Answer:

\mathrm{C.\:}y=\frac{2}{3}x+9

Step-by-step explanation:

In slope-intercept form, the equation of a line is y=mx+b where m is the slope and b is the y-intercept. Plugging in given values, the equation of the is \fbox{$y=\frac{2}{3}x+9$}.

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You are buying a party pack of chips for $14.50 with a 3% tax. How much do you pay in total?
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Answer:

Step-by-step explanation:

The answer is .50

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Work out m and c for the line: y = 4 x − 1
vaieri [72.5K]

Answer:

m=4 and c=-1

Step-by-step explanation:

I'm assuming that m is the slope and c is the y-intercept. (If this is not the case, please tell me and I'll fix my answer).

The equation is already in the form y=mx+c so you just take the numbers from the problem y=4x-1.

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Put in order least to greatest 2/3,60%,0.65,4/5
Nat2105 [25]
60%, 0.65, 2/3, 4/5.
7 0
3 years ago
This is an ADDMATHS question!! It's a kinematics problem. Please help me for both a(i) and a(ii).
Kitty [74]
a(i). Since you are given a velocity v. time graph, the distance will be represented by:
\vec{s}(t) = \int_{a}^{b}\left \| \vec{v}(t) \right \|

In this case, however, we can just use simple geometry to evaluate the area under the graph v(t). I split it up into 2 trapezoids, and 1 rectangle. So, the area will be as follows:
A_t = A_{t1}+A_{t2}+A_r
A_{t1} = \frac{30+15}{2}(10) = 225m
A_{t2} = \frac{15+25}{2}(15) = 300m
A_r = 25(30) = 750m
A_t = 750+300+225 = 1275m

So, the particle traveled a total of 1275m assuming it never turned back (because it says to calculate distance).

a(iii). Deceleration is a word for negative acceleration. Acceleration is the first derivative of velocity, and so deceleration is too. So, we just need to find the slope of the line that passes through t = 30 because it has a linear slope (meaning the slope doesn't change). So, we can just use simple algebra instead of calculus to figure this out. Recall from algebra that slope (m):
m = \frac{y_2-y_1}{x_2-x_1}

So, let's just pick values. I'm going to pick (25, 30) and (35, 15). Let's plug and chug:
m = \frac{15-30}{35-25} = -\frac{15}{10} = -\frac{3}{2}

Since it's a negative value, this means that acceleration is negative but deceleration is positive (because deceleration is negative acceleration). So, your answer is: The deceleration of the particle at t = 30s is 3/2 or 1.5.
5 0
3 years ago
18% of 350 students
Drupady [299]
X       18
350   100

6300/100=63
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