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kirza4 [7]
3 years ago
7

Katie had 4 full cement blocks and one that was 4⁄6 the normal size. If each full block weighed 3 2⁄4 pounds, what is the weight

of the blocks Katie has?
Please show how did you find your answer! Will put as brainliest and top answer!
Mathematics
1 answer:
sveta [45]3 years ago
4 0

Answer:

The weight of the block that Katie has is 16 1/3 pounds

Step-by-step explanation:

<u>Katie has: 4 full cement blocks and 4/6 (or 2/3 ) of the normal size of a cement block</u>

For one full block, it weighs 3 2/4 ( or 1/2) pounds, if you want to find the answer of the question, you need to multiply the weight with the cement blocks that Katie have.

<u>First do the four full cement blocks:</u>

4 * 3 2/4 = ?

4 * 14/4 = ?

Cancel the 4 that is being multiplied and the 4 that is being divided by 14.

= 14.

<u>Now do the 4/6 (or 2/3) cement block:</u>

2/3 * 3 2/4 = ?

2/3 * 14/4 = ?

Multiply the fractions together:

= 28/12

= 2 1/3

<u>Finally, you add up the full blocks and the 2/3 cement block to get your answer:</u>

2 1/3 + 14 = 16 1/3

The weight of the block that Katie has is 16 1/3 pounds

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EleoNora [17]

Answer:

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W  - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

6 0
3 years ago
Two square sheets of cardboard used for making book covers differ in area by 64 square inches. An edge of the larger square is 2
photoshop1234 [79]

Answer:

15 inches

Step-by-step explanation:

We assume that the edge of the small square is x (inches).

As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square  + 2 = x + 2 (inches)

The equation to calculate the are of a square is: <em>Area = Edge^2 </em>

So that:

+) The area of the larger square is: <em>Area large square = </em>(x+2)^{2}<em> (square inches)</em>

+) The area of the smaller square is: <em>Area small square = </em>x^{2}<em>(square inches)</em>

<em />

As difference in area of both squares are 64 square inches, so that we have:

<em>Area large square - Area small square  = 64 (square inches)</em>

<em>=> </em>(x+2)^{2} -x^{2} =64<em />

<em>=>  </em>x^{2}+4x+4  -x^{2} =64<em />

<em>=> 4x + 4 = 64</em>

<em>=> 4x = 64 - 4 = 60 </em>

<em>=> x = 60/4 = 15 (inches)</em>

So the length of an edge of the smaller square is 15 inches

3 0
3 years ago
The midpoint of AB is M(-3,2). If the coordinates of A are (-1, -3), what are
BaLLatris [955]

Answer:

the coordinates of B is (-5,7)

3 0
3 years ago
I need help with this question?
Delicious77 [7]
If I remember right the answer is c
5 0
3 years ago
I want the answer to this problem<br> 3(x+2)-x=38
maks197457 [2]

Answer:

x = 16

Step-by-step explanation:

3(x+2)-x=38

Distribute

3x+6 -x = 38

Combine like terms

2x+6 = 38

Subtract 6 from each side

2x+6-6 = 38-6

2x = 32

Divide each side by 2

2x/2 = 32/2

x = 16

5 0
2 years ago
Read 2 more answers
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