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It would seem the problem requires you compute the mean, median, and standard deviation of each of the data sets. This is nicely done using the statistics functions of your graphing calculator.
Data Set A (mean, median, standard deviation) = (29.7, 29.5, √12.71)
Data Set B (mean, median, standard deviation) = (27.95, 27, √6.1475)
1. False. Data Set B is skewed to the right.
2. TRUE. 27.95 is within 3 of 29.7.
3. False. √12.71 ≠ √6.1475
4. False. The mean of Data Set A is 29.7.
5. False. Data Set A has the higher standard deviation.
6. TRUE. 29.7 is close to 29.5.
The true statements are
• the 2nd one
• the 6th one
Answer:
63m^2
Step-by-step explanation:
Find the area of each base
2.5(10)= 25
1.5(10) = 15
2(10) = 20
Add them together
20 + 15 + 25 = 60
Now find the area of the triangles at each side
2(1.5)(1/2) = 1.5
Since there are two triangles, multiply the area by 2
1.5(2) = 3
Add the areas together
60 + 3 = 63
There's your answer
Answer:
B
Step-by-step explanation:
Because the number of tables have to be less then 140 and you have to multiply to find the number of small tables that can fit
The question requires calculating the perimeter of the rectangular r ug
The equation which represent the situation is 113/2 = 6x + 34/4 and length is 8 inches and width is 20 1/4 inches
Given:
let
length of the rectangular r ug = x inches
Width of a rectangular r ug = <em>(2x + 4 1/4) inches</em>
Perimeter of the r ug = 56 1/2 inches
<em>Perimeter of the r ug = 2(length + width)</em>
56 1/2 = 2{x + (2x + 4 1/4)
113/2 = 2(x + 2x + 17/4)
113/2 = 2(3x + 17/4)
113/2 = 6x + 34/4
113/2 - 34/4 = 6x
(226-34) / 4 = 6x
192/4 = 6x
48 = 6x
divide both sides by 6
x = 48/6
x = 8 inches
So,
length of the rectangular r ug = x inches
= 8 inches
Width of a rectangular r ug = (2x + 4 1/4) inches
= 2(8) + 4 1/4
= 16 + 4 1/4
= 20 1/4 inches
Therefore, the equation which represent the situation is 113/2 = 6x + 34/4 and length is 8 inches and width is 20 1/4 inches
Read more:
brainly.com/question/10452031
