Answer: 5(k)
Step-by-step explanation: “k”times “t” equals 6t-9 so if “k” times “t” equals 21, 6t-9=21, add 9 to 21 which equals 30 so then you divide 30 by 6 to get 5. “t”=5 which means the solution is 5(k)
(I’m just a sixth grader dont blame me if I couldn’t do this)
Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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Answer:
y= -2x - 5
Step-by-step explanation:
You have use to slope intercept and formula to get the answer.
It would be B. because it's just 7 times 1.5
Ok so assuming that the 'x' means multiply and not 'x' as in placeolder we do
PEMDAS
parenthaseees
exponents
multipilcation or division
additon or subtraction
parethasees simplify first
(8+7)=15
(9-3)=6
now we have
2x(15)-6/2x(6)
multiply
2x15=30
6/2x6=36/2=18
now we have
30-18
12
answer is 12