All categories

3 years ago

A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees and totaled $411

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

Answer:

Cost of 1 bushes = a = $9

Cost of 1 tree = b = $73.5

Step-by-step explanation:

Given:

13 bushes and 4 trees cost = $411

Missing;

6 bushes and 2 trees cost = $201

Find:

Value of bushes and tree

Computation:

Cost of 1 bushes = a

Cost of 1 tree = b

So,

13a + 4b = 411 ...........eq1

6a + 2b = 201 ................eq2

From Eq1 and Eq2

Cost of 1 bushes = a = $9

From eq 1

13a + 4b = 411

13(9) + 4b = 411

Cost of 1 tree = b = $73.5

You might be interested in

Which has a larger surface area a prism or a cylinder? Explain

Mila [183]

Answer:

A prism is a solid figure that has two parallel congruent sides that are called bases that are connected by the lateral faces that are parallelograms. ... A cylinder is a tube and is composed of two parallel congruent circles and a rectangle which base is the circumference of the circle.

Step-by-step explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

4 0

3 years ago

Express -23/45 as a decimal

Marrrta [24]

To do this you must divide the two numbers -23÷45 is -0.511111....

8 0

4 years ago

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

CAN SOMEONE PLEASE HELP ME ON THIS ONE !! ITS MY LAST ONE !! PLEASEEEE !!

Ludmilka [50]

Answer:

277.5m²

Step-by-step explanation:

Just multiply.

7 0

3 years ago

GUYS HELP!! What’s an equation that represents the line on the graph?

kenny6666 [7]

Answer:

Hey Mate...

Step-by-step explanation:

All that the slope-intercept form (the equation to describe linear equations) is, is an equation (y=mx+b) where m (the number that multiples x) is the slope and b (the number that is not multiplying a variable on the right-hand side of the equation) is the y-intercept.

3 0

3 years ago