First use distributive property:
2(3n + 4) - 2(2n + 5)
6n + 8 - 4n - 10
Group like terms:
6n - 4n + 8 - 10
Add like terms:
2n - 2
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
<em>Answer:</em>
<em>The perfect squares are the squares of the whole numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 and so on.......</em>
Step-by-step explanation:
Answer:
I CAN!
Step-by-step explanation:
First, where does the line start?
y=1
It looks like it goes up, and then right each one unit. No?
So that would be
Y=1+1
Warning! DO NOT say y=2. That is no good. You probably want to simplify it, but dont. Okay?
Happy to help
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