Answer:
true
Step-by-step explanation:
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
I would tell her not to because not only does she have to pay back the 1000 but now she also has to pay back the interest on it. She should just wait or save up until she has 1000 that way she dont gotta pay extra.
Answer:
b. 25%
Step-by-step explanation:
(new - old)/ old * 100%
150 - 120 = 30 ... 30/120 = .25 * 100% = 25%
Answer:
creti stop deleting my question or i will report ur account
Step-by-step explanation:
