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sineoko [7]
3 years ago
8

Find the sum of 5x+y and (2xy + xy).

Mathematics
2 answers:
Neporo4naja [7]3 years ago
7 0

\displaystyle\ \Large \boldsymbol 5\underline{x^2y}+2xy^2+\underline{x^2y}=5x^2y+x^2y+2xy^2=\boxed{6x^2y+2xy^2}

svetlana [45]3 years ago
4 0

Answer:

6x^2y+2xy^2

Step-by-step explanation:

5x^2y + (2xy^2 + x^2y).

Combine like terms

6x^2y+2xy^2

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Match each equation with its solution set.
taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

 magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

OR

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

OR

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

OR

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I  I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

OR

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0
3 years ago
at cheng's bike rentals, it costs $21 to rent a bike for 6 hours. how many dollars does it cost per hour of bike use?
Vlada [557]
Rent for 6 hours = 21
rent for a hour = 21/6
                        = $3.5
4 0
2 years ago
What is 27÷2356 with the work
Charra [1.4K]
Math answers to fraction 2356 divided by 27 can be calculated as follows.

2356/27 math problems division = 87.2592592593. Therefore 87.2592592593 to 2 decimal places= 87.26

2356/27 divided by 2 » (2356/27) ÷ 2 » 87.2592592593 ÷ 2 = 43.6296296296 .

5 0
3 years ago
Can someone please answer this<br><br> - (6m + 7) -6 (-7 - m) = 35
jasenka [17]

Answer:

35=35

Step-by-step explanation:

-(6m+7)-6(-7-m)=35

-6m-7-6(-7-m)=35

5 0
2 years ago
A colony of bacteria triples in link every 10 minutes. It's length is now 1 mm. How long will be in 40 minutes
Nuetrik [128]
If the bacteria is tripling every 10 minutes, that means the "rate of increase" on that period is 200%, so if say the current amount is "c", 200% of "c" is just 2c, so c + 2c is 3c, a tripled amount.

\bf \textit{Periodic Exponential Growth}\\\\&#10;A=I(1 + r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1\\&#10;r=rate\to 2\%\to \frac{200}{100}\to &2.00\\&#10;t=\textit{elapsed time}\to &40\\&#10;p=period\to &10&#10;\end{cases}&#10;\\\\\\&#10;A=1(1 + 2)^{\frac{40}{10}}
6 0
3 years ago
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